If the diagonals ac and cd of a quardilateral has ob = od and ab = ac prove that it is a parallelgram
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in triangle AOD and triangle BOC
AO is equal to OC
ANGLE 1 IS EQUAL TO ANGLE 2
OB is equal to OD
triangle AOD is congruent to triangle BOC
AD is equal to BC (cpct)
angle 3 is equal to angle 4( cpct )
but angle 3 and 4 are alternat interior angle
therefore , AD is parallel to BC and
AD is equal to BC
then ABCD is a parallelogram
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