If the diagonals of a parallelogram are equal, then show that it is a rectangle.
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Given: Let ABCD be a parallelogram
where AC = BD
To prove: ABCD is a rectangle
Proof: Rectangle is a parallelogram with one angle 90° We prove that one of its interior angles is 90°.
In AABC and ADCB,
AB = DC
BC = BC
AC = DB
ABC = ADCB
ABC = DCB
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