If the Diagonals of a Parallelogram are equal ,then show that it is rectangle.
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Step-by-step explanation:
Ref.Image
□ ABCD is a parallelogram
consider Δ ACD and Δ ABD
AC = BD (given)
AB = DC (opposite sides of parallelogram)
AD = AD (common side)
∴Δ ACD ≅Δ ABD (sss test of congruence)
∠ BAD = ∠ CDA (cpct)
∠BAD+∠CDA=180° [Adjacent angles of parallelogram are supplementary]
so, ∠BAD and ∠CDA are right angles as they are congruent and supplementary.
Therefor, ABCD is a rectangle since a
parallelogram with one right interior angle is a rectangle.
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