Question

If the diagonals of a parallelogram are given by 3i  j  2k and i 3 j  4k , then the length of its sides are

Answer 1

Answer:

Given, 3i−4j−k and 2i+3j−6k

Let sides of a rhombus be a and b.

AC=AB+BC

Therefore, 3i−4j−k=a+b .....(i)

⇒BD=BA+AD

⇒2i+3j−6k=−a+b .....(ii)

On adding equations (i) and (ii), we get

5i−j−7k=2b

⇒∣2b∣=

5

2

+1

2

+7

2

⇒∣b∣=

2

25+1+49

⇒∣b∣=

2

75

=

2

5

3