If the diagonals of a quadrilateral bisect each at right angle, then it is a rhombus (PROVE please) ?
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Answered by
8
heya..
here is your answer...
let us take a quadrilateral ABCD diagonals AC and BD bisect each other at right angle. We have to prove that
A B = B C = C D = A D
AB=BC=CD=AD
In ΔAOB and ΔAOD
D O = O B
DO=OB (O is the midpoint)
A O = A O
AO=AO (common side)
∠ A O B = ∠ A O D
∠AOB=∠AOD (right angle)
So,
Δ A O B ≅ Δ A O D
ΔAOB≅ΔAOD
So,
A B = A D
AB=AD
Similarly
A B = B C = C D = A D
AB=BC=CD=AD can be proved which means that ABCD is a rhombus.
it may help you..
Answered by
1
Hey mate
here's the answer...
Hope it helps ⭐
here's the answer...
Hope it helps ⭐
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