If the diagonals of a quadrilateral bisect each other at a right angle then show that it is a rhombus.
Answers
Answered by
1
Step-by-step explanation:
here is your answer and once try to solve it yourself
Attachments:
Answered by
2
Step-by-step explanation:
Take quadrilateral ABCD , AC and BD are diagonals which intersect at O.
In △AOB and △AOD
DO=OB ∣ O is the midpoint
AO=AO ∣ Common side
∠AOB=∠AOD ∣ Right angle
So, △AOB≅△AOD
So, AB=AD
Similarly, AB=BC=CD=AD can be proved which means that ABCD is a rhombus.
Attachments:
Similar questions