Question

if the diagonals of a rhombus are 10 cm and 24 cm then its area is​

Answer 1

$\large\sf\underline{Question\::}$

• If the diagonals of a rhombus are 10 cm and 24 cm then its area is _____

‎

$\large\sf\underline{Answer\::}$

• The area of the rhombus is $\large{\mathfrak\green{120\:sq.cm}}$

‎ _______________________‎

$\large\sf\underline{Given\::}$

Two diagonals of rhombus :

• Diagonal 1 oR d1 = 10 cm

• Diagonal 2 oR d2 = 24 cm

‎

$\large\sf\underline{To\:find\::}$

• Area of the rhombus

‎

$\large\sf\underline{Formula\:to\:be\:used\::}$

☆ $\large{\mathfrak\blue{Area\:of\:rhombus\:=\:\frac{d1 \times d2}{2}}}$

where :

• d1 = 1st diagonal

• d2 = 2nd diagonal

‎

$\large\sf\underline{Solution\::}$

$\sf\implies\:Area\:=\:\frac{d1 \times d2}{2}$

• Substituting the given values in the formula

$\sf\implies\:Area\:=\:\frac{10 \times 24}{2}$

$\sf\implies\:Area\:=\:\frac{240}{2}$

$\sf\implies\:Area\:=\:\cancel{\frac{240}{2}}$

$\small{\underline{\boxed{\mathrm\red{\implies\:Area\:=\:120\:sq.cm}}}}$ ★

‎_______________________‎

$\large\sf\underline{Some\:more\:formula\:related\:to\:area\::}$

‎

• Area of square = $\sf\:(side) ^{2}$

• Area of rectangle = $\sf\:length \times breadth$

• Area of triangle = $\sf\:\frac{1}{2} \times base \times height$

• Area of circle = $\sf\:πr ^{2}$

• Area of parallelogram = $\sf\:base \times height$

_______________________‎

‎

!! Hope it helps !!

Answer 2

Answer:

$\fbox\pink{Question}$

If the diagonals of a rhombus are 10 cm and 24 cm then its area is

$\fbox\pink{Given}$

D1 = 10 cm

D2 = 24 cm

$\fbox\pink{To\:find}$

We have to find the Area of Rhombus

$\fbox\pink{Formula}$

$Area \: of \: Rhombus = \frac{d1 \times d2}{2}$

$\fbox\pink{Solution}$

D1 = 10 cm

D2 = 24 cm

$Area \: of \: Rhombus = \frac{d1 \times d2}{2}$

= A = $\frac{10 \times 24}{2}$

= 10 × 12

= 120 cm²

•°• Area of Rhombus = 120 cm²

Note:- Refer attachment for the diagram of the question