if the diagonals of a rhombus are 12 cm and 16 cm find the length of each side
Answers
Answered by
1
Answer:
Your answer is 10.
Step-by-step explanation:
12/2 = 6
16/2 = 8
Pythagoras theorem ,
(6)² + (8)² = (H)²
36 + 64 = (H)²
100 = (H)²
√100 = H
√(10)² = H
10 = H
So , length of each side is 10cm.
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Answered by
1
Answer:
DC = 10 cm
Step-by-step explanation:
OD = 8 cm and OC = 6 cm { Diagonals bisect each other perpendicularly. }
OD^2 + OC^2 = DC^2
8^2 + 6^2 = DC^2
64 + 36 = DC^2
DC^2 = 100
DC = 10 cm
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