Math, asked by simabh12, 8 months ago

if the diagonals of a rhombus are 12 cm and 16 cm find the length of each side​

Answers

Answered by vatskashish01
1

Answer:

Your answer is 10.

Step-by-step explanation:

12/2 = 6

16/2 = 8

Pythagoras theorem ,

(6)² + (8)² = (H)²

36 + 64 = (H)²

100 = (H)²

√100 = H

√(10)² = H

10 = H

So , length of each side is 10cm.

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Answered by adhithyama
1

Answer:

DC = 10 cm

Step-by-step explanation:

OD = 8 cm  and   OC = 6 cm  { Diagonals bisect each other perpendicularly. }

OD^2 + OC^2 = DC^2

8^2 + 6^2 = DC^2

64 + 36 = DC^2

DC^2 = 100

DC = 10 cm

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