if the diagonals of a rhombus are 12 cm and 16cm,find the length of its side.
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Given : d1 = 12cm and d2= 16cm Now, perimeter= 2√[(d1)^2+(d2)^2]
=2√[(12)^2+(16)^2]cm
=2√[144+256]cm
=2√400 cm
=2√(20)^2 cm
2×20 cm = 40 cm
We know that, Perimeter of rhombus is also : 4 × side
Therefore, 4×s = 40 cm
Therefore, side = 40/4 cm =10cm{Ans}
Hope it helps!!
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