Question

If the diagonals of a rhombus are 12cm and 16cm find the length of each side.
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Answer 1

By using pathagorean formula

${h}^{2} = {b}^{2} + {p}^{2} \\ {h}^{2} = {6}^{2} + {4 }^{2} \\ {h}^{2} = 36 + 16 \\ {h}^{2} = 52 \\ {h} = \sqrt{52 } cm \\ \sqrt{52} is \: a \: side \: of \: rhombus$

Answer

Answer 2

Question:-

The lengths of the diagonals of a rhombus are 16cm and 12cm. then find the length of the side of rhombus

Solution:-

we know that diagonal of rhombus,bisect each other in right angle ( 90° ).

we also know that all sides of rhombus are equal ( of equal length ).

so, now

Let rhombus is ABCD

Let, diagonal of rhombus

BD = 16 cm and AC = 12 cm

means,

OD = 8 cm and AO = 6 cm

By pythagorus theorem

To find length of AD ( and all side of rhombus )

=> (AD)² = (OD)² + (AO)²

=> (AD)² = (8)² + (6)²

=> (AD)² = 64 + 36

=> (AD)² = 100

=> AD = √100

=> AD = 10 cm

Hence length of all side of rhombus

is 10 cm.

i hope it helps you.