Question

If the diagonals of a rhombus are
24 cm and 10 cm, what is its perimeter?​

Answer 1

Answer:

P = 52 cm

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Hi ,

Let d1 , d2 are diagonals of the Rhombus ,

d1 = 24cm

d2 = 10 cm

area = ( d1 d2 ) / 2

A = ( 24 × 10 ) / 2

A = 120 square cm

Let side if the Rhombus = a cm

a² = ( d1/2 )² + ( d2/2 )²

= ( 24 / 2 )² + ( 10 /2 )²

= ( 12 )² + 5²

= 144 + 25

= 169

a = √169

a = 13 cm

perimeter of the Rhombus = 4a

P = 4 × 13

P = 52 cm

I hope this helps you.

:)