if the diagonals of a rhombus are 24 dm and 10dm then the perimeter of the Rhombus will be
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In rhombus diagonals are 24 dm and 10 dm
We know formula of perimeter=2
(digonal)
2
+(digonal)
2
Then perimeter of rhombus =2
(24)
2
+(10)
2
=2
576+100
=2×26=52 dm
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