Question

If the diagonals of a rhombus are 24cm and 10cm the area and the perimeter of the rhombus are respectively.

Answer 1

Answer:

Area = 1/2 * 24 * 10

        = 120 cm^2.

Perimeter s² = (24/2)^2 + (10/2)^2

 

                       =  12^2 + 5^2

                      =   169

                  s = 13.

The perimeter of the rhombus = 4 * 13 = 52cm.

Answer 2

Answer:

area of rhombus

$= \frac{1}{2} \times( product \: of \: diagonals)$

$= \frac{1}{2} \times (10 \times 24) = 120 {cm}^{2}$

now perimeter of rhombus

$= 4 \times ( \sqrt{ { \frac{(diagonal1)}{2} }^{2} + { \frac{(diagonal2)}{2} }^{2} }$

$= 4 \times \sqrt{{ (\frac {24}{2} )}^{2} + { (\frac{10}{2} )}^{2}} \\ = 4 \times \sqrt{ {12}^{2} + {5}^{2} } \\ = 4 \times 13 = 52cm$