Question

If the diagonals of a rhombus are 86cm and 2 m long, Find its area.

Answer 1

Answer:

area=143cm^2

Step-by-step explanation:

area=1/2(d1+d2)

=1/2(86+200)

=1/2(286)

=143 cm^2

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Answer 2

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$\bold{Explanation:}$

Given :

Diagonals of a rhombus are 86cm and 2m

To Find :

Area of Rhombus

Some Properties of Rhombus:

$\implies$ Rhombus is a type of quadrilateral having four sides and four vertices.

$\implies$All sides are equal and parallel.

$\implies$ Diagonals bisect each other at $90^{\circ}$angle.

One of Diagonal is given in metre so we convert into cm

$\sf 2m=2\times100=200\:cm$

$\boxed{\sf Area \:of\:Rhombus=\dfrac{D_{1 }\times D_{2}}{2}}$

=>Where D are diagonals.

$\boxed{\sf Area = \dfrac{86 \times 200}{2} = 8600 {cm}^{2} \: or\: 0.86{m}^{2}}$