Question

if the diagonals of a rhombus are ac 16 cm and bd is 12 cm find the side of the rhombus


​

Answer 1

Answer:

10 cm

Step-by-step explanation:

Side of a rhombus = $\sqrt{\frac{d_{1} }{2}^{2} + \frac{d_{2} }{2}^{2} }$

Side = $\sqrt{(\frac{16 }{2})^{2} + (\frac{12 }{2})^{2} }$

Side = Sqrt(8^2 + 6^2) = Sqrt(64 + 36) = Sqrt(100) = 10cm

Answer 2

Answer:

The Rhombus is ABCD, we now in a rhombus diagonals bisect each other  

So AO=CO=16/2=8cm

and BO=DO=12/2=6cm

In  RIGHT triangle ABO

AB²=OB²+OA²

      =6²+8²=36+64=100

So AB=10cm

In rhombus all sides are equal so AB=BC=DC=DA=10cm