If the diagonals of a rhombus are equal, prove that it is a square.
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ABCD is a rhombus, in which diagonals AC and BD are equal.
We know that diagonals of rhombus bisect each other.
As AC=BD
∴AO=BO=CO=DO
In △AOB,
⇒AO=OB and ∠AOD=90°
∴∠OAB=∠OBA=
2
90
o
=45°
Similarly in △AOD,
⇒∠OAD=∠ODA=45°
∴∠A=∠OAB+∠OAD=45
o
+45
o
=90°
Similarly,
⇒∠B=∠C=∠D=90°
here, AB=BC=CD=DA
∴ Quadrilateral ABCD is a square.
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