Question

If the diagonals of a rhombus measure 10 cm and 24 cm,find its perimeter

Answer 1

Perimeter = 1/2×d1×d2
=1/2×10×24
=120 cm

Answer 2

In rhombus diagonals bisect each other at right angles. And the side will be hypotenuse.

So, half the diagonals = 12cm & 5cm

Side ² = 12² +5² = 144+ 25 = 169

= side = √169= 13cm

=> perimeter = 13 * 4 =52 cm ( as all four sides are equal)

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