Question

If the diagonals of rhombus are 12cm and 16cm find the length of each side​

Answer 1

Answer:

Thank you guys.

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Answer 2

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• $\bf\:BD=12\:cm$

• $\bf\:AC=16\:cm$

${\bold{\pink{\underline{\pink{To}\:\purple{Fin}\blue{d}\red{:-}}}}}$

• Length of each side=??

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$\bf\:BD=12\:cm\:(given)$

$\bf\:OD=\dfrac{1}{2}\:BD$

$\bf\:OD=\dfrac{1}{2}\times\:12$

$\bf\green{{OD=6\:cm}}$

then,

$\bf\:AC=16\:cm\:(given)$

$\bf\:OA=\dfrac{1}{2}\:AC$

$\bf\:OA=\dfrac{1}{2}\times\:16$

$\bf\red{{OA=8\:cm}}$

Now,

$\bf\boxed\star\orange{\underline{\underline{{Using\:Pythagoras\:theorem}}}}$

$\bf\:A{D}^{2}=O{A}^{2}+O{D}^{2}$

$\bf\:A{D}^{2}={8}^{2}+{6}^{2}$

$\bf\:A{D}^{2}=64+36$

$\bf\:A{D}^{2}=100$

$\bf\:AD=\sqrt{100}$

$\bf\blue{{AD=10\:cm}}$

$\bf\green{{\therefore}}$All the four sides are 10 cm each.