If the diagonals of rhombus are 16 cm and 12 cm then find its area and perimeter.
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Answer:40cm²,96cm²
Explanation:Use Pythagorean’s, AO=16/2=8,BO=12/2=6
In AOB,
AB² =AO²+BO²
AB²=8²+6²
AB²=64+36
AB²=100√10=10cm²
Then use the perimeter of rhombus formula,
=4×Side
10×4=40cm²
area of a rhombus =1/2×D1×D2=1/2×16×12=96cm²
so this is the answer first bisect each other of a diagonal,then multiply by ×4. Sorry for the late , hope it helps you pls mark me as brainliest
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