Question

if the diagonals of rhombus are 72 cm and 96 cm, then the height of the side of rhombus is

Answer 1

We have to apply Pythagoras theorem

We know the diagonals of rombus bisect at 90 degree

and the diagonals are also bisected

so the length of the bisected diagonals are (1/2*72)cm = 36cm and (1/2*96)cm = 48cm


applying Pythagoras theorem that is

base^2 + perpendicular ^2 = hypotenuse ^2

considering hypotenuse (side of rombus) as x

we get,

x^2 = (36)^2 +(48)^2
=1296 + 2304
=3600
x = √3600
=60


therefore length of each side is 60cm