if the diagonals of the Rhombus are 12 cm and 16 cm find the length of each side
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Hiii friend,
Let ABCD is a RHOMBUS in which,
AB = AD = BC = DC.
Let Diagonal AC = 12 cm
And,
Diagonal BD = 16 cm
OA = 1/2 × AC = 1/2 ×16 = 8 cm
And,
OB = 1/2 ×AC = 1/2 × 12 = 6 cm
By pythagoras theroem,
Side (AB)² = (OA²+OB²)
AB² = (8)² + (6)²
AB² = 64+36
AB² = 100
AB = ✓100 = 10 cm
Hence,
Side of rhombus is 10 cm
HOPE IT WILL HELP YOU....... :-)
Let ABCD is a RHOMBUS in which,
AB = AD = BC = DC.
Let Diagonal AC = 12 cm
And,
Diagonal BD = 16 cm
OA = 1/2 × AC = 1/2 ×16 = 8 cm
And,
OB = 1/2 ×AC = 1/2 × 12 = 6 cm
By pythagoras theroem,
Side (AB)² = (OA²+OB²)
AB² = (8)² + (6)²
AB² = 64+36
AB² = 100
AB = ✓100 = 10 cm
Hence,
Side of rhombus is 10 cm
HOPE IT WILL HELP YOU....... :-)
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