if the diameter of a cylinder is half then find the ratio between the volume of new and the old one
Answers
Answered by
5
let diameter is x
and volume is 1
the ratio is x:1
and volume is 1
the ratio is x:1
dee16:
But this is not the answer
Answered by
21
Hey mate..
=========
Given,
Diameter of the new cylinder = d/2
Thus,
Radius of the new cylinder = 1/2 × d/2 = d/4
Now,
Volume of the new cylinder with that of the old cylinder
=![\frac{ \frac{1}{3}\pi \: r {}^{2} h }{ \frac{1}{3} \pi \: r {}^{2} h} \frac{ \frac{1}{3}\pi \: r {}^{2} h }{ \frac{1}{3} \pi \: r {}^{2} h}](https://tex.z-dn.net/?f=+%5Cfrac%7B+%5Cfrac%7B1%7D%7B3%7D%5Cpi+%5C%3A+r+%7B%7D%5E%7B2%7D+h+%7D%7B+%5Cfrac%7B1%7D%7B3%7D+%5Cpi+%5C%3A+r+%7B%7D%5E%7B2%7D+h%7D+)
=![\frac{ \frac{1}{3} \pi( \frac{d}{4}) {}^{2}h }{ \frac{1}{3} \pi \: ( \frac{d}{2} ) {}^{2} h} \frac{ \frac{1}{3} \pi( \frac{d}{4}) {}^{2}h }{ \frac{1}{3} \pi \: ( \frac{d}{2} ) {}^{2} h}](https://tex.z-dn.net/?f=+%5Cfrac%7B+%5Cfrac%7B1%7D%7B3%7D+%5Cpi%28+%5Cfrac%7Bd%7D%7B4%7D%29+%7B%7D%5E%7B2%7Dh+%7D%7B+%5Cfrac%7B1%7D%7B3%7D+%5Cpi+%5C%3A+%28+%5Cfrac%7Bd%7D%7B2%7D+%29+%7B%7D%5E%7B2%7D+h%7D+)
=![\frac{ \frac{d {}^{2} }{16} } { \frac{d {}^{2} }{4} } \frac{ \frac{d {}^{2} }{16} } { \frac{d {}^{2} }{4} }](https://tex.z-dn.net/?f=+%5Cfrac%7B+%5Cfrac%7Bd+%7B%7D%5E%7B2%7D+%7D%7B16%7D+%7D+%7B+%5Cfrac%7Bd+%7B%7D%5E%7B2%7D+%7D%7B4%7D+%7D+)
=![\frac{4}{1} \frac{4}{1}](https://tex.z-dn.net/?f=+%5Cfrac%7B4%7D%7B1%7D+)
= 4 : 1
#racks
=========
Given,
Diameter of the new cylinder = d/2
Thus,
Radius of the new cylinder = 1/2 × d/2 = d/4
Now,
Volume of the new cylinder with that of the old cylinder
=
=
=
=
= 4 : 1
#racks
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