if the diameter of a sphere is decrease by 25% then what is the curved area would decrease
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radius r
so r bcomes 3/4r (25% decrease )
so suface area is 4(3/4r)^2
which is 9/4r^2
so change percentage is
(4r^2-9/4r^2)/4r^2×100=7/16×100%
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vibha94:
can you explain me step wise please
actually first ur taking radius as r then ur find csa for radius r the comparing when r is decreases by 25/100 which 3/4r
ok then
after that
what to do
can you explain me last calculation part
then u need to find change percentage which is actual or initial minus after the change divided by initial multiplied to hundered it is exactly the loss percentage formula
can you send step wise photos of calculation please
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