Question

If the diameter of a wire is doubled keeping its length the same , what happens to its Young's modulus of elasticity...........

Answer 1

Like we know the expression for Youngs modulus…..

Y = (F×dL)/A×L

So kepping F L comstants…

Y is inversly proportional Area of cross section so incresing diameter increses area..

But surprise to notice YOUNG’S modulus is a total contant…. :-))*

dL may change accordingly…

Therefore YOUNG’S MODULUS does not change

But other quantities adjust themselves to cop up with the changes….

Hope u got it…

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