If the diameter of a wire is doubled, without
altering other parameters, the resistance will
become ............ of its original resitance.
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0
Answer:
the resistance will become 1/4 of its original resistance
Answered by
0
Answer:
by the relation of drift velocity and... current flowing in the circuit ... I = neav....
where I= current flowing in the circuit
number of electrons = n , e = charge on electron
a = area of the circuit
v drift velocity.... put the relation in v= IR
R=V/I .... a= π r^2 so if diametre doubles .... r also doublesd ...so t square becomes 4 times of r... so the resistance will be 1/4R
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