If the diameter of circle is 40 cm then what is the distance between two chords of length 24 cm and 32 cm
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Since the chord is 20cm & diameter is 40 cm.
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The chord & the radii to the chord ends forms an equilateral Triangle.
Angle subtended by the arc at centre is pi/3.
Minor arc = r x (pi/3) = 20 x 3.1415/3 = 20.94 cm…
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The chord & the radii to the chord ends forms an equilateral Triangle.
Angle subtended by the arc at centre is pi/3.
Minor arc = r x (pi/3) = 20 x 3.1415/3 = 20.94 cm…
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