If the diameter of each cylinder formed by him is 16 cm, then height of each of them is *
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Answer:
The required area = Area of ΔABC − 3× Area of 60
∘
sectors
=(
4
3
×8
2
)−(3×
360
60
×π4
2
)
=16
3
−8π=8(2
3
−π)cm
2
Required volume = Area of region × height
= 16×8(2
3
−π)
=128(2
3
−π)cm
3
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