If the diameter of earth reduces in half what would be the duration of day
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First Scenario(mass remains the same)
Now if mass remains the same, new moment of inertia will be I'=I/4
And according to law of conservation of angular momentum (Iw=I'w').
w'=4w
Also w=2π/T and w'=2π/T'
T'=T/4
T=24 hours
T'=24/4= 6 hours
Hence a day would be one- fourth of current duration
Second Scenario(mass changes according to volume)
if density of the Earth remains same then
mass=M, volume=V, density=d
M=V*d
V=(4/3)πR^3
V’=new volume
V’=V/8
M’=M/8
I=(2/5)MR^2
I’=(2/5)M’R’^2
I’=I/32
I’w’=Iw
w’=32w
w'=2π/T'
w’T’=wT
T’=T/32
T’=24/32=45 minutes
Although this is only theoretical assumption, in practical many more changes have to be faced from nature
Hope it helps...☺
Now if mass remains the same, new moment of inertia will be I'=I/4
And according to law of conservation of angular momentum (Iw=I'w').
w'=4w
Also w=2π/T and w'=2π/T'
T'=T/4
T=24 hours
T'=24/4= 6 hours
Hence a day would be one- fourth of current duration
Second Scenario(mass changes according to volume)
if density of the Earth remains same then
mass=M, volume=V, density=d
M=V*d
V=(4/3)πR^3
V’=new volume
V’=V/8
M’=M/8
I=(2/5)MR^2
I’=(2/5)M’R’^2
I’=I/32
I’w’=Iw
w’=32w
w'=2π/T'
w’T’=wT
T’=T/32
T’=24/32=45 minutes
Although this is only theoretical assumption, in practical many more changes have to be faced from nature
Hope it helps...☺
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