If the diameter of the base of a closed right circular cylinder be equal to its height 'h', then its whole surface area is
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problem is solved in picture plzz check out
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vinayakshishodia:
but the answer is 3/2 pi h square
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Answer:
Total Surface Area of the Cylinder is 3/2 × π × h² unit²
Step-by-step explanation:
Given: Diameter of the Right circular cylinder , d = h
Height of the cylinder , h
To find: Total Surface Area of the cylinder.
We know that Total surface area of the cylinder = 2πr ( r + h )
r = d/2 = h/2
So,
Total Surface Area of the cylinder = 2 × π × (h/2) × ( h/2 + h )
= π × h ( 3h/2 )
= 3/2 × π × h²
Therefore, Total Surface Area of the Cylinder is 3/2 × π × h² unit²
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