Math, asked by shubhamsharma1241, 1 year ago

If the diameter of the circular ends of a bucket which is 16cm high are 40cm and 16cm. Find the capacity and total surface area of the bucket

Answers

Answered by Anonymous
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Answered by wifilethbridge
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The total surface area and volume of bucket are 3218.28 sq.cm. and 210459.42 cubic cm respectively.

Step-by-step explanation:

Shape of bucket is frustum

Height of bucket = 16 cm

Diameter of bigger end = 40 cm

Radius of bigger end R=\frac{40}{2}=20 cm

Diameter of smaller end =16 cm

Radius of smaller end r=\frac{16}{2}=8 cm

Volume of bucket =\frac{1}{3} \pi h (r^2+R^2+Rr)=\frac{1}{3} \times \frac{22}{7} \times 16 (8^2+20^2+(8)(20))=10459.42 cm^3

Total surface area of frustum =\pi (r+R) \sqrt{(R-r)^2+h^2}+\pi r^2+\pi R^2

Total surface area of frustum =\frac{22}{7}(20+8) \sqrt{(20-8)^2+16^2}+\frac{22}{7}(8)^2+\frac{22}{7}(20)^2=3218.28 cm^2

Hence The total surface area and volume of bucket are 3218.28 sq.cm. and 210459.42 cubic cm respectively.

#Learn more:

If the radii of the circular ends of a conical bucket which is 32cm high are 40cm and 16cm find the capacity of total surface area of the bucket?

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