Question

if the diameter of the cylindrical vessel be decreased by 5% then by how much percent will its length be increased if its volume remains unchanged?​

Answer 1

Answer:

here is the answer

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Answer 2

Answer:

Step-by-step explanation:

Diametre be d

radius be d/2

vol=πr*r*h

=πd*d*h/4

if d is increased by 5% then d=5%of d

d=5/100*d

d=d/20

19d/20

∴r=2*19d/20=19d/40

vol=πd*d*h/4

π*19d/40*19d/40*h

∴h=400d/361 ( calculate the above one)

increase in length=400h/361-l =39l/361

%of increase =39h/361/h*100=3900/361% =10.80%.