Question

if the difference and product of two numbers are 5 and 36 respectively. Then their reciprocal differ by (a) 5/36 (b)31/36 (c)5/9 (d) 9/5

Answer 1

Let the larger number be x and the smaller number be y

So we have

x−y=5

x∗y=36

and we need to find 1/y−1/x(since x>y, 1/y>1/x)

1/y−1/x=(x−y)/(x∗y) (cross-multiplication)

1/y−1/x=5/36//this is your answer i think it may help you