Question

if the difference between areas of the circumcircle and the incircle of an equilateral triangle is 44 cm2 then the area of the triangle is

Answer 1

Let the side of the triangle be 'a' cm

⇒Circumradius=a/√3

and Inradius

=a/2√3

⇒π(a/√3)^2−π(a/2√3)^2=44

⇒π(a^2/3−a^2/12)=44

⇒4a^2−a^2/12=44×7/22=14

⇒3a^2/12=14

⇒a^2=56

⇒a^2√14

⇒area

=√3/4×2√14

=14√3cm^2

Answer 2

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