If the difference between compound interest and simple interest on certain sum of money for 3 years at 5% per annum is ₹122, find the sum.
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Answered by
5
x be the Principal.
CI = P * (1 + R/100)^N - P where CI is Compound Interest, P is Pincipal, R is rate of Interest & N is No. of years.
And SI = PNR/100 where SI is Simple Interest & all other terms are same as above.
x * (1 + 5/100)^3 - x - x * 3 * 5/100 = 122
i.e. x * 1.05^3 - x - 0.15x = 122
i.e. 1.157625x - x - 0.15x = 122
i.e. 0.007625x = 122
i.e. x = 122/0.007625
i.e. x = 16000
So, the Principal is Rs. 16,000/-.
Answered by
4
Answer:
16000
Step-by-step explanation:
given,
C.I - S.I =122
P(1+5/100)^3-P-(P*5*3/100)=122
P{(105/100)^3-1-15/100}=122
P(7625/1000000)=122
P=122*1000000/7625
P=16000
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