if the difference between S.I and C.I for 2 years on a sum of money lent at 5%per annum is RS.6 then the sum is
Answers
Answered by
0
Sum = D *100^2 /r^2
D = difference, ^2 = 2 yeaars, r = rate of int
Sum = 50 x 100 x100 /10*10 = Rs 5000 ANSWER
Answered by
1
Here,
R = 5% pa , T = 2 yrs and CI - SI = 6
Then,
SI = PRT/100
SI = P×5×2/100
SI = P/10
CI = A - P
= P(1+(R/100))^T - P
= P (1+ (5/100))² - P
= P { (1+(5/100))² - 1 }
= P { (1 + (1/20))² - 1 }
= P { (21/20)² - 1 }
= P { (441/400) - 1 }
= P { 41/400 }
A/Q,
CI - SI = 6
P { 41/400} - P/10 = 6
P { (41/400) - (1/10) } = 6
P { (41 - 40) / 400 } = 6
P { 1/400} = 6
P = 6 × 400
P = 2400
Similar questions