Question

if the difference between S.I and C.I for 2 years on a sum of money lent at 5%per annum is RS.6 then the sum is​

Answer 1

$\fbox\orange{A}\fbox\pink{N}\fbox\blue{S}\fbox\red{W}\fbox\purple{E}\fbox\red{R}$

Sum = D *100^2 /r^2

D = difference, ^2 = 2 yeaars, r = rate of int

Sum = 50 x 100 x100 /10*10 = Rs 5000 ANSWER

Answer 2

Here,

R = 5% pa , T = 2 yrs and CI - SI = 6

Then,

SI = PRT/100

SI = P×5×2/100

SI = P/10

CI = A - P

= P(1+(R/100))^T - P

= P (1+ (5/100))² - P

= P { (1+(5/100))² - 1 }

= P { (1 + (1/20))² - 1 }

= P { (21/20)² - 1 }

= P { (441/400) - 1 }

= P { 41/400 }

A/Q,

CI - SI = 6

P { 41/400} - P/10 = 6

P { (41/400) - (1/10) } = 6

P { (41 - 40) / 400 } = 6

P { 1/400} = 6

P = 6 × 400

P = 2400