If the difference between the compound and the simple interest of a sum of money for 3 years at the rate of 10% per annum is ₹ 620
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Answer:
3000$ pls give brainlest
Step-by-step explanation:
Given:
Interest rate =10% per annum
Time =3 years.
We know that:
Simple interest (SI)=PTR/100
where P is principle amount, T is time taken, R is rate per annum
Let sum is P, then
SI=(P×3×10)/100
⇒SI=(30P)/100
⇒SI=(3P)/10 —————- equation 1
To find the amount we have the formula,
Amount (A)=P(1+(r/100))
n
where P is present value, r is rate of interest, n is time in years.
Also CI=A−PNow substituting the values in above formula we get,
∴CI=P(1+10/100)
3
−P
⇒CI=P(1+1/10)
3
−P
⇒CI=P(11/10)
3
−P
⇒CI=P(1331)/(1000)–P
⇒CI=331P/1000 ——– equation 2
Now the difference is
(CI–SI)=331P/1000–(3P)/10
$$\RIghtarrow 93 = 331P- 300P/1000$$
⇒93=31P/1000
⇒P=93×1000/31
⇒P=3×1000
⇒P=3000
∴ Sum $$= ₹\3000$$
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