Math, asked by samriddhibhatia7, 8 months ago

If the difference between the compound interest and simple interest on Rs 42000 for 2 years is Rs 105 at the same rate of interest per annum, then the rate of interest is 5%, the compound interest for two years is rs. 4305. the amount after two years will be ​

Answers

Answered by mona0002004
0

Step-by-step explanation:

P = Rs 42000 T=2 years

Let rate = r %

S.I=

100

PRT

=

100

42000×r×2

=840 Rs

For C.I

A=P(1+

100

r

)

n

=42000(1+

100

r

)

2

=42000(1+

10000

r

2

+

50

r

)

=42000+

10

42r

2

+840r

C.I = A - P

=42000+

10

42r

2

+840r−42000

=

10

42r

2

+840r

Given C.I−S.I=105

=

10

42r

2

+840r−840r=105

=

10

42r

2

=105

=42r

2

=1050

=r

2

=25

r=5%

C.I at 2nd year = 42000(1+

100

5

)

2

−42000

=42000(1.1025−1)=4305 Rs

Answered by iTzRiYaNsH
0

Answer:

P = Rs 42000 T=2 years

Let rate = r %

S.I=

100

PRT

=

100

42000×r×2

=840 Rs

For C.I

A=P(1+

100

r

)

n

=42000(1+

100

r

)

2

=42000(1+

10000

r

2

+

50

r

)

=42000+

10

42r

2

+840r

C.I = A - P

=42000+

10

42r

2

+840r−42000

=

10

42r

2

+840r

Given C.I−S.I=105

=

10

42r

2

+840r−840r=105

=

10

42r

2

=105

=42r

2

=1050

=r

2

=25

r=5%

C.I at 2nd year = 42000(1+

100

5

)

2

−42000

=42000(1.1025−1)=4305 Rs

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