If the difference between the probability of success and failure of an event is 4/13. Find the probability of success and failure of the event.
Answers
see the attached pic for answer
Given :-
♦ The difference between the probability of success and failure of an event is 4/13
To find :-
♦ The probability of success and failure of the event .
Solution :-
Let the probability of success of an event be P(S)
Let the probability of failure of the event be P (F)
They are complementary events.
So, P(S) + P(F) = 1 --------------(1)
Given that
The difference between the probability of success and failure of the event = 4/13
=> P(S) - P(F) = 4/13 -----------(2)
On adding (1) & (2) then
P(S) + P(F) = 1
P(S) - P(F) = 4/13
(+)
_______________
2 P(S) + 0 = 1+(4/13)
_______________
=> 2 P(S) = 1+(4/13)
=> 2 P(S) = (13+4)/13
=> 2 P(S) = 17/13
=> P(S) = (17/13)/2
=> P(S) = 17/26
On substituting the value of P(S) in (1)
=> (17/26)+P(F) = 1
=> P(F) = 1-(17/26)
=> P(F) = (26-17)/26
=> P(F) = 9/26
Therefore, P(S) = 17/26 and P(F) = 9/26
Answer :-
The Probability of success of the event = 17/26
The Probability of failure of the event = 9/26
Used formulae:-
♦ The sum of the probabilities of the two complementary events in a trial is 1.
♦ If the probability of an event E is P(E) then P(E) + P(not E) = 1.