If the difference between the side of a right angled triangle is3 cm and it's area is54 cm square .Find it's perimeter
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Let the two sides be x and x + 3
Area = 54 cm^2
1/2 (x)(x+3) = 54
x² + 3x = 108
x² + 3x - 108 = 0
(x+12)(x-9) = 0
x = 9
Sides are 9 cm and 12 cm
Hypotenuse = √9^2+12^2
= √81+144
= √225
= 15 cm
Perimeter of triangle = 9 + 12 + 15 = 36 cm
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