If the difference between the sides of a right angled triangle is 3cm and its area is 54; find its perimeter.
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take one side as x
so other side become x-3
area of triangle is half of product of perpendicular sides
so,
54=x×(x-3)
by solving this quadratic equation
you will get
x=12 or x=-9
x is not equal to -9 because length of side is always positive
x=12
x-3=9
using Pythagoras theorem
diagonal is 15cm
perimeter=9+12+15=36
perimeter of the triangle is 36cm
so other side become x-3
area of triangle is half of product of perpendicular sides
so,
54=x×(x-3)
by solving this quadratic equation
you will get
x=12 or x=-9
x is not equal to -9 because length of side is always positive
x=12
x-3=9
using Pythagoras theorem
diagonal is 15cm
perimeter=9+12+15=36
perimeter of the triangle is 36cm
Dev0708:
how did you get that?? thats the correct answer
i will explain it in picture
ok thanks
hey where is the method??
method was saved in answer
you can solve middle steps easily
well i was confused which sides the question was asking about and whether it was all the sides because it said the difference of sides
thanks
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