Question

If the difference between the simple and the compound interest earned on a sum of money at the rate of 5 p.c.p.a. for 2 years is Rs. 16. Find the principal.

Answer 1

Answer:

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Answer 2

If the difference between the simple and the compound interest earned on a sum of money at the rate of 5 p.c.p.a. for 2 years is Rs. 25. Find the principal.

P=(I×100)/(R×T)

P=(I×100)/(R×T)Compound interest formula

P=(I×100)/(R×T)Compound interest formula=> FV = P×(1+R/100})^T

P=(I×100)/(R×T)Compound interest formula=> FV = P×(1+R/100})^T Here FV = P + Total Interest

P=(I×100)/(R×T)Compound interest formula=> FV = P×(1+R/100})^T Here FV = P + Total Interest => I = P×(1×R/100)^T -P

P=(I×100)/(R×T)Compound interest formula=> FV = P×(1+R/100})^T Here FV = P + Total Interest => I = P×(1×R/100)^T -P So by equating condition mentioned in question where R=5% and T=2 years and difference is 25

P=(I×100)/(R×T)Compound interest formula=> FV = P×(1+R/100})^T Here FV = P + Total Interest => I = P×(1×R/100)^T -P So by equating condition mentioned in question where R=5% and T=2 years and difference is 25=>(P×R×T)/100+25=P×(1+R/100)T−P

P=(I×100)/(R×T)Compound interest formula=> FV = P×(1+R/100})^T Here FV = P + Total Interest => I = P×(1×R/100)^T -P So by equating condition mentioned in question where R=5% and T=2 years and difference is 25=>(P×R×T)/100+25=P×(1+R/100)T−P=>(P×5×2)/100+P×(1+5/100)2−P

P=(I×100)/(R×T)Compound interest formula=> FV = P×(1+R/100})^T Here FV = P + Total Interest => I = P×(1×R/100)^T -P So by equating condition mentioned in question where R=5% and T=2 years and difference is 25=>(P×R×T)/100+25=P×(1+R/100)T−P=>(P×5×2)/100+P×(1+5/100)2−P=>(10P+2500)/100=P∗(1.05)2−P

P=(I×100)/(R×T)Compound interest formula=> FV = P×(1+R/100})^T Here FV = P + Total Interest => I = P×(1×R/100)^T -P So by equating condition mentioned in question where R=5% and T=2 years and difference is 25=>(P×R×T)/100+25=P×(1+R/100)T−P=>(P×5×2)/100+P×(1+5/100)2−P=>(10P+2500)/100=P∗(1.05)2−P=>(10P+2500)/100=0.1025P

P=(I×100)/(R×T)Compound interest formula=> FV = P×(1+R/100})^T Here FV = P + Total Interest => I = P×(1×R/100)^T -P So by equating condition mentioned in question where R=5% and T=2 years and difference is 25=>(P×R×T)/100+25=P×(1+R/100)T−P=>(P×5×2)/100+P×(1+5/100)2−P=>(10P+2500)/100=P∗(1.05)2−P=>(10P+2500)/100=0.1025P=>(10P+2500)=10.25P

P=(I×100)/(R×T)Compound interest formula=> FV = P×(1+R/100})^T Here FV = P + Total Interest => I = P×(1×R/100)^T -P So by equating condition mentioned in question where R=5% and T=2 years and difference is 25=>(P×R×T)/100+25=P×(1+R/100)T−P=>(P×5×2)/100+P×(1+5/100)2−P=>(10P+2500)/100=P∗(1.05)2−P=>(10P+2500)/100=0.1025P=>(10P+2500)=10.25P=>0.25P=2500

P=(I×100)/(R×T)Compound interest formula=> FV = P×(1+R/100})^T Here FV = P + Total Interest => I = P×(1×R/100)^T -P So by equating condition mentioned in question where R=5% and T=2 years and difference is 25=>(P×R×T)/100+25=P×(1+R/100)T−P=>(P×5×2)/100+P×(1+5/100)2−P=>(10P+2500)/100=P∗(1.05)2−P=>(10P+2500)/100=0.1025P=>(10P+2500)=10.25P=>0.25P=2500=>P=2500/0.25

P=(I×100)/(R×T)Compound interest formula=> FV = P×(1+R/100})^T Here FV = P + Total Interest => I = P×(1×R/100)^T -P So by equating condition mentioned in question where R=5% and T=2 years and difference is 25=>(P×R×T)/100+25=P×(1+R/100)T−P=>(P×5×2)/100+P×(1+5/100)2−P=>(10P+2500)/100=P∗(1.05)2−P=>(10P+2500)/100=0.1025P=>(10P+2500)=10.25P=>0.25P=2500=>P=2500/0.25=>10000