If the difference between the total surface area and the lateral surface area of a cuboidal object ise 392 cmsquare. Find its total surface area
Answers
Answer:
Step-by-step explanation:
- The total surface area of the given cubical object is equal to 1176 cm² .
Given :- The difference between the total surface area and the lateral surface area of a cubical object is 392cm² .
To Find :- Total surface area of the cubical object ?
Formula used :-
- Total surface area (TSA) of cube = 6a²
- Lateral surface area (LSA) of cube = 4a²
- where a is the length of each side of the cube .
Solution :-
Let us assume that, the length of each side of given cubical object is equal to a cm .
So,
→ Total surface area of cubical object = 6a²
and,
→ Lateral surface area of cubical object = 4a²
A/q,
→ Total surface area of cubical object - Lateral surface area of cubical object = 392 cm²
→ 6a² - 4a² = 392
→ 2a² = 392
dividing both sides by 2,
→ a² = 196
→ a² = (±14)²
square root both sides,
→ a = ± 14 cm
since length of sides of a cubical object can't be in negative . Therefore, we can conclude that, the length of each side of given cubical object is equal to 14 cm .
therefore,
→ Total surface area of cubical object = 6a²
putting a = 14 cm we get,
→ Total surface area of cubical object = 6•(14)²
→ Total surface area of cubical object = 6 × 196
→ Total surface area of cubical object = 1176 cm² (Ans.)
Hence, required total surface area is equal to 1176 cm² .
Shortcut :-
→ 6a² - 4a² = 392
→ 2a² = 392
dividing both sides by 2,
→ a² = 196
therefore,
→ TSA = 6a² = 6 × 196 = 1176 cm² .
Learn more :-
The diagram shows a window made up of a large semicircle and a rectangle
The large semicircle has 4 identical section...
https://brainly.in/question/39998533
a rectangular park is of dimensions 32/3 m ×58/5 m. Two cross roads, each of width 2 1/2 m, run at right angles through ...
https://brainly.in/question/37100173