If the difference between the two sides
of a right-angled triangle is 2 cm and
the area of the triangle is 24 cmsq find
the perimeter of the triangle.
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the given
difference between two side =2
height - base =2
height = 2+base
let base = x
so height = x+2
area of rectangle triangle = 24
1/2×base ×height=24
1/2× X × (X+2)=24
X(X+2)= 24×2
X^2+2x=48
{x}^{2} + 2x - 48 = 0
{x}^{2} + (8 - 6)x - 48 = 0
{x }^{2} + 8x - 6x - 48 = 0
x(x + 8) - 6(x + 8) = 0
(x + 8)(x - 6) = 0
x - 6 = 0
x = 6
so base = 6
height = 6+2=8 answer
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