Question

If the difference between two numbers is

3 and difference between their squares is 39,

then what will be the larger number?​

Answer 1

Answer:

Step-by-step explanation:

Let the larger number be x, and the smaller number be y.

Therefore,

x - y = 3, and x^2 - y^2 = 39

x^2 - y^2 = (x + y )(x -y)

= (x + y) *3 = 39

Therefore,

x +y = 39/3 = 13

Therefore,

x + y + x - y = 13 + 3

Therefore,

2*x = 16

Therefore,

x = 16/2 = 8.

Therefore,

y = x - 3 = 5.

Therefore, the larger number, x = 8.

Good luck!

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Answer 2

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$\LARGE{\bf{\mathtt{\purple{GivEn}}}}$

• Difference between 2 numbers = 03

• Difference between squares of the numbers = 39

$\:\:$

$\LARGE{\bf{\mathtt{\purple{ToFinD}}}}$

• Larger number.

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$\LARGE{\bf{\mathtt{\purple{ConSeDeRinG}}}}$

• Let the larger number be x

• Let the smaller number be y

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$\LARGE{\bf{\mathtt{\purple{SoLuTioN}}}}$

Therefore ,

$\:\:$

➜$\large{\bf{x-y=3\:and\:x²-y²=39}}$

$\:\:$

➜$\large{\bf{x²-y²=(x+y)(y-x)}}$

$\:\:$

➜$\large{\bf{(x+y)×3=39}}$

$\:\:$

Therefore ,

➜$\Large{\bf{x+y={\frac{39}{3}}}}$ = 13

$\:\:$

➜ $\large{\bf{x+y+x-y=13+3}}$

$\:\:$

➜ $\large{\bf{2x=16}}$

$\:\:$

➜ $\Large{\bf{\frac{16}{2}}}$

$\:\:$

➜ $\large{\bf{\green{X=8}}}$

$\:\:$

➜ $\large{\bf{y=x-3=5}}$

$\:\:$

therefore , the larger number is x = 08

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