Physics, asked by baahu73, 11 months ago

if the difference in the mass of reactant and mass of product in a nuclear reaction is 0.02 amu what is the energy released in one reaction​

Answers

Answered by Anonymous
4

heya..

here is you answer..

Given,

The difference in the mass of reactant and mass of product in a nuclear reaction is 0.02 amu.

Then energy released in one reaction = 0.02 amu = 931×0.02 = 18.62 MeV.

It may help you..☺☺

Answered by AadilAhluwalia
0

Given,

The difference in Mass of reactant and Mass of product= 0.02 amu

To Find,

Energy Released in One Reaction.

Solution,

We know that the value of 1 amu is 931 MeV.

So, according to this,

0.02 amu = 931\times0.02 = 18.62 MeV

Hence, the energy released in one reaction is 18.62 MeV.

Similar questions