Question

if the difference of 16th term and 12th term of the given ap is 18 then the common difference is equals to

Answer 1

Answer:

Given: a16-a12=18

an=a+(n-1)d

a+15d-a-11d=18

4d=18

d=9/2=4.5

Hpe it hlps u

Answer 2

The common difference is equals to 4.5.

Explanation:

Let a = First term in an Arithmetic progression

d= Common difference.

Formula : nth term in A.P. = $a_n=a+(n-1)d$

Then, 16th term : $a_{16}=a+(16-1)d=a+15d$

12th term : $a_{12}=a+(12-1)d=a+11d$

As per given :

$a_{16}-a_{12}=18\\\\ a+15d-(a+11d)=18\\\\ 15d-11d=18\\\\ 4d=18\\\\ d=\dfrac{18}{4}=4.5$

Hence, the common difference is equals to 4.5.

# Learn more :

The 11th term of AP is 38 and the 16th term is 73.find the common difference

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