If the difference of 2 number is8 the difference of their square s 160 then
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x-y = 8 ---------(1)
x^2-y^2 = 160
=> (x+y)*(x-y)= 160
=> x+y = 20 ---------(2)
solve 1 & 2
x=14, y = 6
x^2-y^2 = 160
=> (x+y)*(x-y)= 160
=> x+y = 20 ---------(2)
solve 1 & 2
x=14, y = 6
Anonymous:
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Answered by
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the numbers are 14 and 6
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