if the difference of an AP is 2, then find a5-a3.(not only answer, i need full step by step)
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Step-by-step explanation:
a
3
=a+2d
⟹2=a+2d
⟹a=2−2d
a
2
=a+d=2−2d+d=2−d
a
4
=a+3d=2−2d+3d=2+d
a
5
=a+4d=2−2d+4d=2+2d
∑
i=1
5
a
i
=a
1
+a
2
+a
3
+a
4
+a
5
=2−2d+2−d+2+d+2+2d
=10
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