If the difference of areas of the circumcircle and the incircle of a square is 154 sq cm then what is the area of the square?
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Let the height of the triangle be h units and three sides of the triangle be x cm.
⇒ h2 + (x/2)2 = x2
∴ h = √3x/2
⇒ Radius of the circumcircle = 2/3 × h = x/√3
⇒ Radius of incircle = 1/3 × h = x/2√3
⇒ π(x2/3 – x2/12) = 154
⇒ 22/7 × x2/4 = 154
⇒ x = 14
∴ Area of the equilateral triangle = √3/4 × 14 × 14 = 49√3 cm2
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