If the difference of the digits of a 2 digit no is 3 and the sum of the number and the number obtained on reversing the digit is 165. Find the number?
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The sum of 2 digit number and the number obtained by reversing the order of the digit is 165. If the digit differ by 3, find the number , when ten's digit is bigger than the unit 's digit. Hence both the conditions are verified. 96 is the required number
or
So by applying the given conditions we get the following equations:
(10x+y)+(10y+x)=165 ————–(i)
x-y=3 ——————-(ii)
11x+11y=165
Taking out 11 as a common factor
x+y=15 ———————-(iii)
Solving (ii) and (iii) we get,
2x=18
x=9
y=15–9=6
Hence the number is 96
Verification:
We can verify by substituting the values in the given conditions:
96 + 69 = 165
9-6=3
Hence both the conditions are verified.
96 is the required number.
Step-by-step explanation:
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